There are 9592 prime numbers less than 100,000. Assuming the test suite only tests numbers 1-99999, the accuracy should actually be only 90.408%, not 95.121%
In response to the question of how long it would take to round up to 100%:
The density of primes can be approximated using the Prime Number Theorem: 1/ln(x).
Solving 99.9995 = 100 - 100 / ln(x) for x gives e^200000 or 7.88 × 10^86858. In other words, the universe will end before any current computer could check that many numbers.
Hi there! Looks like you linked to a Lemmy community using a URL instead of its name, which doesn’t work well for people on different instances. Try fixing it like this: !programmer_humor@programming.dev
I think a more concise answer to the second one would be; it depends on where you decide to round, but as you run it, it approaches 100%, or 99.99 repeating (which is 100%)
The screenshot displays 3 decimal places, which is the the precision I used. As it turns out, even just rounding to the nearest integer still requires checking more numbers than we even have the primes enumerated for (e^200 or 7x10^86)
A few calculations I did last time I saw this meme (over at !programmer_humor@programming.dev):
In response to the question of how long it would take to round up to 100%:
1/ln(x)
. Solving99.9995 = 100 - 100 / ln(x)
for x givese^200000
or7.88 × 10^86858
. In other words, the universe will end before any current computer could check that many numbers.Edit: Fixed community link
Hi there! Looks like you linked to a Lemmy community using a URL instead of its name, which doesn’t work well for people on different instances. Try fixing it like this: !programmer_humor@programming.dev
I think a more concise answer to the second one would be; it depends on where you decide to round, but as you run it, it approaches 100%, or 99.99 repeating (which is 100%)
The screenshot displays 3 decimal places, which is the the precision I used. As it turns out, even just rounding to the nearest integer still requires checking more numbers than we even have the primes enumerated for (e^200 or 7x10^86)
Ah, ok yeah that makes sense.